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D dx e4lnx • d dx esin2x • d dx ln cose2x Solution Simplify it before the differentiation e4lnx = elnx 4 = x4 ⇒ d dx e4lnx = d dx x4 = 4x3 By the chain rule, d dx esin2x = esin2x d dx sin2x = esin2x ·2cos2x By the chain rule, d dx ln cose2x = 1 cose2x · −sine2x · d dx e2x = −2e2x tane2x 22 Graphing Graph of f(x) = e−x 2 2 6.
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