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T = K V = −½mκ²/(n ²h²) If total energy decreases by ΔT half of the decrease goes into increased kinetic energy and the other half goes into an emitted photon Thus the energy γ is given by γ = ½(mκ²/h²)(1/n F ²−1/n I ²) where n I is the initial quantum number for the electron and n F is its final quantum number The photon energy U is converted into wavelength λ via the. ¤ î ½ 0 ¸ Á Ü Z M ï ò KWWSV ZZZ SUHI QDJDQR OJ MS GRFWRU NHQNR GRFWRU MXMLVKD IDT KWPO Title Microsoft Word é ·é ç ç è·è ·å ¡ä¿®å¦è³ é ã ã ã ã 質å docx Author N Created Date 3/5/21 AM. 0 ©¹ n x t v Z §· ¨¸ ©¹ 2/10/14 Spring 14 14 k;.
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