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Xbg vy1 4b. H g ^ Z j _ g d h I h e b g Z e _ d k _ _ \ g Z11 d e Z k k J m k k d b c. _ T m ¥. 3 / 3 (c) Yes Suppose (u, v) is a particular but arbitrarily chose element in the codomainThen, u and v are both real numbers Let x = 1v and y = (u1)/3Then, x and y are also both real numbers So, (x, y) is in the domainBy the definition of F, we have F( , )=F(1− , 1 3)=(3∙ 1 3 −1,1−(1− ))=( , ) (d) Yes, because F is both injective and surjective.

= ( x 2) 1 Note that (f B g)(x) ≠ (g B f)(x) This means that, unlike multiplication or addition, composition of functions is not a commutative operation The following example will demonstrate how to evaluate a composition for a given value Example 6 Find (f B g)(3) and (g B f)(3) if f ( x ) = x 2 and g ( x ) = 4 – x2 Solution. L>*#'/ d _4 I O G \ v M 0 1 ¦* 7�/õ. Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and more.

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Hoi, wat is bij y= 1/2 x g x t 2 de y?. Provided to YouTube by IngroovesSet Me Free . Substituting this into the original equation x 2 xy y 2 = 3 leads to (2y) 2 (2y) y y 2 = 3 , 4 y 2 2y 2 y 2 = 3 , 3y 2 = 3 , y 2 = 1 , and Thus, the maximum value of x occurs when y=1 and x=2 , ie, at the point (2, 1) The minimum value of x occurs when y=1 and x=2 , which occurs at the point (2, 1) Click HERE to return.

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